3sin^2*x-sinx*cosx=2

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Solution for 3sin^2*x-sinx*cosx=2 equation: 


Simplifying
3sin2 * x + -1sinx * cosx = 2

Multiply in2s * x
3in2sx + -1sinx * cosx = 2

Multiply insx * cosx
3in2sx + -1cinos2x2 = 2

Reorder the terms:
-1cinos2x2 + 3in2sx = 2

Solving
-1cinos2x2 + 3in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
-1cinos2x2 + 3in2sx + -3in2sx = 2 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
-1cinos2x2 + 0 = 2 + -3in2sx
-1cinos2x2 = 2 + -3in2sx

Divide each side by '-1inos2x2'.
c = -2i-1n-1o-1s-2x-2 + 3no-1s-1x-1

Simplifying
c = -2i-1n-1o-1s-2x-2 + 3no-1s-1x-1

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